Prove that : sin(90° - θ)sin θ/tan θ - 1 = -sin^2 θ - Sarthaks

Prove that : sin(90° - θ)sin θ/tan θ - 1 = -sin2 θ

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sin(90-theta)×cos(90-theta)÷tan theta=1-sin^2 theta

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Prove: (1 – sin θ) / (1 + sin θ) = (sec θ – tan θ)^2 - Sarthaks eConnect

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Prove that: (sin θ - 2 sin^3 θ) / (2 cos^3 θ - cos θ) = tan θ [Video]

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