trigonometry - Proving that $\tan \theta=\cot(90^\circ-\theta)$ when $\theta>90^\circ$ - Mathematics Stack Exchange

I'm asked to prove $\tan \theta=\cot (90-\theta)$ So $\tan \theta =\frac{a}{b}=\cot(90^\circ-\theta)$ But what if $\theta>90?$

Cosec (90 + theta) + cot (450 + theta)÷cosec(450 - theta) - tan

Prove that ( frac { cot left( 90 ^ { circ } - theta right) } { tan theta } + frac { csc left( 90 ^ { circ } - theta right) cdot sin theta } { tan left( 90 ^ { circ } - theta right) } = sec ^ { 2 } theta )

Trigonometric functions - Wikipedia

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Right Triangle Trigonometry

Find the exact value of tan 90° - GeeksforGeeks

CORDIC - Wikipedia

10.3: The Six Circular Functions and Fundamental Identities

cot left(frac{90-theta}{tan theta}+frac{csc (90-theta) sin theta

Prove that : (cot(90^(@)-theta))/(tantheta)+(cosec(90^(@)-theta)sint