Bengali] If A+B=90^(@) then prove that 1+(tanA)/(tanB)=sec^(2)A.

A+B=90^(@)impliesB=90^(@)-A :.1+(tanA)/(tanB)=1+(tanA)/(tan(90^(@)-A)) =1+(tanA)/(cotA)=1+tanA.tanA =1+tan^(2)A=sec^(2)A. Hence 1+(tanA)/(tanB)=sec^(2)A.

If A + B = 90°, then (tan A tan B + tan A cot B)/(sin A sec B

If a+b=90 prove that root of tanatanb+tanacotb/sinasecb

How is tan(A+B) = (tanA+tanB) /1-tanAtanB? - Quora

A+B=90,then find tanA tanB +tanA cotB/sinA secB - sin^2B/cos^2A

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Bengali] If alpha+beta=90^(@) then prove that cosec^(2)alpha+cosec^(2

यदि A =B=60^(@)हो , तो प्रमाणित करो कि tan

Bengali] If A+B=90^(@) then prove that 1+(tanA)/(tanB)=sec^(2)A.

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